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2014-04-15T11:18:52+03:00
Sin<B=2/3⇒  cos<B=3/2     cos<B=AB/BC

3/2=√5/BC
BC=2√5/3

AC²=BC²-AB²=(2√5/3)²-(√5)²=20/9 -5   =20-45/9=-25/9   ⇒AC=-5/3

A=AB*AC/2=√5*(-5/3)/2=    -5√5/3 /2=  -5√5/3 *1/2=- 5√5/6