Răspunsuri

2014-04-14T11:38:00+03:00
A/11=b/3 =>a=11b/3

(7a-2b)/(3a+5b)
(7*11b/3-2b)/(3*11b/3+5b)
(77b/3-2b)/(33b/3+5b) //amplificam 2b cu 3 si 5b cu 3
(71b/3)/(48b/3)=71b/48b=71/48
6 3 6
Cel mai inteligent răspuns!
2014-04-14T11:45:00+03:00
A=11,b=3⇒7·11-2·3=77-6=71  ,   3·11+5·3=33+15=48⇒71supra48
4 4 4