Răspunsuri

2014-04-14T02:21:42+03:00
Mas<AOC=x
mas<BOC=y
x+y/ 2=64 30'
x+y=2*64 30'
x+y=128 60'
x,y ip cu 1,3
⇒1*x=3y=k
x=3y=k
x=k     y=k/3
k +k/3=128 60' aducem la acelasi numitor
3k+k=386 20'  (385 80'= 386 20')
4k=386 20'
k=96 55'
x=96 55'    y=96 55'/3=32 18'