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2014-04-13T23:01:10+03:00
Notăm a+2010=x și b+1=y

(x+y)^2=xy ⇒  x^{2} +2xy+y^2=xy ⇒ x^2+xy+y^2=0

x^2+xy+ \frac{1}{4}y^2+ \frac{3}{4}  y^2=0

(x+ \frac{1}{2}y)^2+ \frac{3}{4}y^2=0

 \left \{ {{(x+ \frac{1}{2}y)^2 =0} \atop { \frac{3}{4}y^2 =0}} \right.  ⇒ x=y=0

 \left \{ {{a+2010=0} \atop {b+1=0}} \right.  ⇒  \left \{ {{a=-2010} \atop {b=-1}} \right.