Răspunsuri

2014-04-07T17:56:09+03:00
A-b=12⇒a=b+12
a:b=3(rest 2)⇒a=3b+2
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a=b+12=3b+2
⇒b+12=3b+2⇒2b=10⇒b=5⇒a=5+12⇒a=17.
2014-04-07T19:37:30+03:00
A:b=3 rest 2 ⇒a=3b+2 (teorema impartirii cu rest)
a - b=12 a=b+12
a /----/----/----/..2..
b /----/ ,,,,12,,,,,
12-2=10 (suma a 2 segm egale)
10:2=5 (b)
a=5+12=17