Răspunsuri

2014-04-03T21:36:32+03:00
2014-04-03T21:37:45+03:00
Xla a2a+x+2x+2=x(x+1)+2(x+1)=(x+1)(x+2)
xla a2a+2x+3x+6=x(x+2)+3(x+2)=(x+2)(x+3)
xla a2a +3x+4x+12=x(x+3)+4(x+3)=(x+3)(x+4)
xla a2a-10x+25-9=(x-5)la a2a -9=[(x-5)+3][(x-5)-3]=(x-2)(x-8)
xla a2a -x-6x+6=x(x-1)-6(x-1)=(x-1)(x-6)
xla a2a-4x-5x+20=x(x-4)-5(x-4)=(x-4)(x-5)
xla a2a +2x+6x+12=x(x+2)+6(x+2)=(x+2)(x+6)
xla a2a-5x-10x+50=x(x-5)-10(x-5)=(x-5)(x-10)
multumesc mult
imi mai rezolvi un exercitiu te rog?
cu placere sigur