Un gospodar are gaini,gaste si oi.stiind ca in total sunt 71 de capete si 172 de picioare,afla cate gaini,gaste si oi are gospodarul,daca numarul gastelor este m ai mic de 3 ori decat numarul gainilor.

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Răspunsuri

2014-04-02T18:43:06+03:00
A+b+c=71
2a+2b+4c=172
a=3b
6b+2b+4c=172
8b+4c=172
4c=172-8b
c=43-2b
3b+b-2b=71-43
            =28
14(a)
14x3=42(b)
43-28=15(c)

2014-04-02T20:17:13+03:00
A=gaini
b=gaste=3a
c=oi
a+b+c=71
172/71=2 r 30
(30+30)/4=15 oi
71-15=56 gaini+gaste
a+3a=56
4a=56
a=56/4
a=14 gaini
b=3*a
b=3*14
b=42 gaste
                               R:15 oi, 14 gaini, 42 gaste