Răspunsuri

  • Utilizator Brainly
2014-03-30T21:48:53+03:00
X+y+z=496 ⇒ 4x+4y+4z=1984;
4x+6y+9z=2009 ⇒ 2y+5z=25 (2y par, 25 impar deci 5z impar, z<5, impar): vor fi 2 cazuri:
a) z=1, y=10, x=485;
b) z=3, y=5, x=488