Răspunsuri

2014-03-30T18:02:26+03:00
CM=c%*ro*10/masa molara a HNO3
cM=20*1,12*10/63=3,55 moli/litru
cM=nr moli/volum=>nr moli = cM * volum = 3,55*0,5 = 1,77 moli HNO3 = 112 g HNO3
c%=md/ms * 100=>ms=md/c*100=112/5 * 100=>ms = 2240 g solutie
ms = md + m apa=>m apa = 2240 - 112 = 2128 g apa