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2014-03-30T13:53:11+03:00
2 HCl + CaCO3 ---> CaCl2 + H2O + CO2
la 100 g CaCO3........2*36,5 g HCl
la 200 g CaCO3.........x g HCl      x = 4*36,5=146g HCl=md
c%=md/ms*100=>ms=md/c * 100=>ms=146/18,25 * 100=>ms=800g HCl
la 1 mol CaCO3.........1 mol CO2
la 200 g CaCO3=2 moli...........x moli CO2        x=2 moli CO2
V total = nr moli * 22,4=>V total = 2*22,4=>V CO2 = 44.8 litri
 
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