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2014-03-29T22:45:17+02:00
CM=c% * ro * 10/masa molara acid
cM=98 * 1,84 * 10/98 = 18,4 molari
cM=nr moli/volum =>nr moli = cM * volum = 0.5 * 0.2 = 0,1 moli acid
conc molara finala = nr moli acid/volum final
volum final = nr moli acid/cM final = 0.1/18.4=>volumul = 0,00543 l = 5,43 ml acid
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