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2014-03-29T19:14:15+02:00


M NaOh=11+16+1=28 g/mol

m NaOH=10 g

10 gNaOH ....................................16 g O

28g..........................................x

x=16*28/10=44,8

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2014-03-29T22:38:55+02:00
In 40 g NaOH se gasesc 16 g O
in 10 g NaOH se gasesc x g O     x = 4 g O
masa molara NaOH = A sodiu + A oxigen + A hidrogen = 23+16+1=40 g/mol
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