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2014-03-26T14:28:02+02:00
Ca(OH)2 + H2SO4 ---> CaSO4 + 2 H2O
a)puritatea=masa pura/masa impura * 100
masa pura var = 80 * 2/100=1,6 tone var pur
la 74 g Ca(OH)2..........40 g Ca
la 1,6 tone Ca(OH)2.........x g Ca              x = 0,86486 tone = 864,86 kg Ca
b)la 74 g Ca(OH)2......98 g H2SO4
la 1,6 tone Ca(OH)2......y g H2SO4           y = 2,11892 tone H2SO4
c%=md/ms * 100 =>ms=md/c * 100 = 2,11892/30 * 100 => ms = 7,06307 tone solutie

Masa molara Ca(OH)2 = A calciu + 2 * A oxigen + 2 * A hidrogen = 40+32+2=74g/mol
Masa molara H2SO4 = A hidrogen + A sulf + 4 * A oxigen = 2+32+64=98g/mol
In toata aceasta problema te folosesti de ecuatia reactiei chimice si folosesti regula de 3 simpla pt a afla cantitatile cerute