Răspunsuri

2014-03-25T16:28:48+02:00
H2CO3 - raport de masa: 2:12:48 = 1:6:24

%H=masa hidrogen/masa molara acid * 100 = 2/62 * 100
% C = masa carbon/masa molara acid * 100 = 12/62 * 100
%O = masa oxigen/masa molara acid  * 100 = 48/62 * 100

Al(OH)3 -raport 27:48:3 = 9:16:1
masa molara = 27+2 * 17 = 61 g/mol
%Al=27/61 * 100       %H=3/61 * 100          %O=48/61*100

(NH4)2CO3 raport 28:8:12:48=7:2:3:12
masa molara=18 * 2 +12+48=96 g/mol

Na2O raport 46:16 = 23:8
masa molara = 2*23+16=62g/mol

CuSO4 (acesta este sulfatul nu ce ai scris tu!!) raport: 64:32:64=2:1:2
masa molara = 64+32+64=160g/mol

Fe2O3 = 108:48=36:8=9:2
masa molara = 2*56+48=156g/mol

Procentele la fiecare se calculeaza dupa formula de mai sus,iar raportele se calculeaza in fct de nr de atomi din molecula inmultita cu masa atomica a acelui element.