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2014-03-23T20:20:04+02:00
106 g Na2CO3.......48 g O
424 g NaOH.............x g O          x=192 g O

 
2014-03-23T20:23:29+02:00
Calculezi masa moleculara a sodei de rufe
M Na₂CO₃ = 106
Daca in 106 g Na₂CO₃ ....48 g O₂
         In 424 g Na₂CO₃......x g O₂

x=48 * 424 /106 =192 g O₂

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