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2014-03-20T15:28:50+02:00
BaCl2 + H2SO4 ---> BaSO4(acesta va fi precipitatul) + 2 HCl
masa moleculara sulfat = 244+32+64 = 340 g/mol
la 98 g H2SO4.........340 g BaSO4
la x g H2SO4...........466 g BaSO4          x = 134,31765 g H2SO4 = md
c%=(md/ms)*100=>ms = (md/c)* 100 =(134,31765/20)*100=>ms = 671,588 g H2SO4 

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