Răspunsuri

2014-03-15T21:29:59+02:00
143 -3-10=130 (d+i)
r<i 10<11 ,12.......
d =11*3+10=43   43 +11+3+10=65
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cauti solutii 
2014-03-15T22:50:30+02:00
A:b=3 rest 10 ⇒ a=3b+10   (1)
a+b+3+10=143 ⇒ a+b= 130  (2)
Inlocuiesc (1) in (2) si obtin
3b+10+b=130 ⇒ 4b=130-10=120 ⇒ b=30 si a = 3*30+10=100
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