In triunghiul ABC oarecare, se duc: AD Perpendicular pe BC, D∈(BC) si BE perpendicular pe AC, E∈(AC)
a)Daca AC=16cm, BE=9cm, AD=8cm, calculati Aria ΔABC si BC
b)Daca AC=15cm, BC=9cm, AD=10cm, calculati Aria ΔABC si BE
c)Daca ARIA ΔABC=45,5cm, AD=7cm, AC=13cm, calculati BC, BE

1

Răspunsuri

Cel mai inteligent răspuns!
2014-11-18T10:20:58+02:00
A=bxh/2

A)Aabc=BExAC/2=ADXBC/2
A=BEXAC/2=9x16/2=72cm² dar si ADXBC/2=72⇒8xBC/2=72⇒BC=2x72/8=18
b)Aabc=ADXBC/2=10x9/2=45
BExAC/2=45⇒BEx15/2=45⇒BE=45x2/15=6
c)Aabc=BExAC/2⇒45,5=BEx13/2⇒BE=45,5x2/13=7
Aab=ADXBC/2⇒45,5=ADx7/2⇒AD=45,5x2/7=13



27 4 27