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2014-11-17T19:38:47+02:00
Zn+H2So4=ZnSo4+ H2

86,6/100×15=12,99 substanta pura 
MZn=65⇒1 mol de zn =65 g
MH2=2⇒1 mol de H2 =2g
realizati proportia ⇒   65/12.99=2/x⇒x= 0,39g  H2
n=m/M⇒n=0,39×2=0,78moli H2

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2014-11-17T19:40:59+02:00