Răspunsuri

2014-11-17T20:29:21+02:00
Din Δ dreptunghicDAB
DB²=DA²+AB²
DB²=36+36
DB=6√2 cm

din ΔDAC
DC²=AD²+AC²
DC²=36+36
DC=6√2 cm

AM in triunghiul echilateral ABC este nu numai mediana dar si inaltime
AM²=AB²-BM²
AM²=36-9=25
AM=5 din Δ dr.DAM
DM²=DA²+AM²
DM²=36+25=61
DM=√61