Răspunsuri

2014-11-15T18:00:29+02:00
Nr. pare =(2438+2·0), (2438+2·1), (2438+2·2),........(2438+2·636)
S pare = 2438·637 +2(1+2+3+.......+636) = 2438·637 + 2·636·637/2 =
= 2438·637 + 636·637 = 637(2438 + 636) = 637·3074 = 1958138
nr. impare= (2439+2·0), (2439+2·1), (2439+2·2),........(2439+2·636)
S impare =2439·637 +2·636·637/2 = 637(2439+636)= 637·3075 =1958775

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