Răspunsuri

2014-11-15T14:00:08+02:00
AA'=CC'=12 \sqrt{3}
Din Teorema lui Pitagora in triunghiul BCC' dreptunghic in C⇒BC la a 2-a= CC' la a 2-a +CB la a 2-a
24²=(12√3)²+ CB²
CB²=576-432
CB²=144
CB=√144
CB=12 cm
ABCA'B'C'-prisma Δ reg, dr,⇒CB=AB=AC=12⇒P_{ABCA'B'C'} =4·12=48cm
;)