Ajutati-ma va rog NEAPARAT
calculati: k
√64 √144 √196 √5929 √2la puterea a 10 √3la puterea a 8·5la puterea a6 √3² (k∈N)
CALCULATI:
a)√16 ; √49 ; √81 ; √400 ; √2500 ; √6400 ; 3600
b)√121 ; √169 ; √196 ;√ 625 ; √441 ;√576 ; 729

2

Răspunsuri

2014-11-14T23:05:28+02:00
√64 = 8
√144 = 12 
√196 = 14√5929 = 77
√2 LA A 10-A = 2 LA A 5-A
√3 LA A 8-A = 3 LA A 4-A
√5 LA A 6-A = 5 LA A 3-A
√3² =√9 = 3
A) √16 = 4
√49 = 7 
√81 = 9
√400 = 20
√2500 = 50
√6400 = 80
√3600 = 60
B) √121 = 11
√169 = 13
√196 = 14
√625 = 25
√441 = 21 
√576 = 24
√729 = 27
2014-11-14T23:05:37+02:00
 \sqrt64=8 , \sqrt144=12,  \sqrt196=14 ,  \sqrt5929=77 , \sqrt2 ^{10} =32,  \sqrt3 ^{8}=81,  \sqrt{5}^{6}=75  \sqrt{3}^{2}=3
a)  \sqrt{16} =4,  \sqrt{49} =7 , \sqrt{81} =9,  \sqrt{400}=20,   \sqrt{2500} =50,  \sqrt{6400}=80 ,  \\  \sqrt{3600} =60,
b) \sqrt{121} =11,  \sqrt{169} =13,  \sqrt{196} =14,  \sqrt{625} =25,  \sqrt{411} =21,  \sqrt{576} =24,   \sqrt{729} =27 
(uhh... am terminat , greu sa scrii cu radicali :D)