Răspunsuri

2014-11-14T08:41:50+02:00
[√2(x-1)-8x][√2(x-1)+8x]=(√2x-√2-8x)(√2x-√2+8x)=[x(√2-8)-√2][x(√2+8)-√2]
asta in situatia in care doar (x-1)²
[5(x+2)-4][5(x+2)+4]=(5x+6)(5x+14)
[2(x+3)-3x][2(x+3)+3x]=(6-x)(5x+6)