Răspunsuri

2014-11-13T22:14:37+02:00
2x2³x3²:18+5x{625:5³+[(3x3²x5²)¹⁷:(9²⁵x25¹⁷)+6⁵x3⁵]x2³la puterea0}
2¹⁺³x3²:2x3²+5x{5⁴:5³+[(3¹⁺²x5²)¹⁷:((3²)²⁵x(5²)¹⁷+2⁵x3⁵x3⁵]x2¹}=
2⁴⁻¹x3²⁻²+5x{5⁴⁻³+[(3³x5²)¹⁷:(3⁵⁰x5³⁴)+2⁵x3⁵⁺⁵]x2}=
2²x3°+5x{5+[(3⁵¹x5³⁴):(3⁵⁰x5³⁴)+2⁵x3¹⁰]X2}=
4X1+5X{5+[3⁵¹⁻⁵⁰X5³⁴⁻³⁴+2⁵X3¹⁰]X2}=
4+5X{5+[3X5°+2⁵X3¹⁰]X2}=
4+5X{5+[3X1+2⁵X3¹⁰]X2}=
4+5X{5+(3+2⁵X3¹⁰]X2}=
4+5X{5+[3X2+2⁵⁺¹X3¹⁰]}=
4+5X{5+6+2⁶X3¹⁰}=
4+5X{11+2⁶X3¹⁰}=
4+55+2⁶X3¹⁰=
49+2⁶X3¹⁰=

CEVA NU E IN REGULA LA EX
stiu, asta mi s-a parut si mie dar asa e in carte
daca vrei si poti, ma mai ajuti la un exercitiu plees :)
e pe pagina mea, cel care nu are raspuns
dau raspuns castigator