Răspunsuri

2014-11-11T21:14:52+02:00
30.
3.(2^49.2-1)/(2-1):(4^24.4-1)/(4-1)=
3.(2^50-1)/1:[(2^2)^24.2²-1)/3=
3.(2^50-1)/1:(2^50-1)/3=
3.(2^50-1)/1x3/(2^50-1)=3x3=9
se foloseste formula 
s=(ultimul numar xratia-1)/(ratia-1)

1-primul
1.2=2 al doilea
1.2.2=2^2-al treilea deci fiecare termen se formeaza din anteriorul inmultit cu 2 (ratia)
S=(2^49.2-1)/2-1=(2^50-1)/1

29.
7^45(7
²+7-1):7^43(7²+7-1)+156:(13^9:13^8)=
7²+156:13=49+12=61


2 5 2