Răspunsuri

2014-11-11T18:08:55+02:00
2014-11-11T18:13:42+02:00
Z=1³ +3*1² *i + 3*1i²+i² + 1² - 2*1i +i²
z=1³ + 3*i + 3i²+i²+1-2i+i²
z=1³+3i+3i²+i²+1-2i+i2
ultimele doua se reduc
z=2+3i +3i²+i

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