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2014-11-11T17:22:22+02:00
(x+3)²+2(x-4)(x+3)+(x-4)²
(x+3)²=x²+6x+9
(x-4)(x-3)=X²+3x-4x-12
(x-4)²=x²-8x+16
⇒x²+6x+9+2x²-2x-24+x²-8x+16=4x²-4x+1
Δ=16-16=0
x=4/8=1/2
(x+1)(1-3x)=x-3x²+1-3x=-3x²-2x+1
Δ=4-4(-3)*1=4+12=16
x₁=(2+4)/(-6)=-1
x₂=(2-4)/(-6)=1/3