Răspunsuri

2014-11-10T19:51:42+02:00
100a+10b+c+100b+10c+a+100c+10a+b=
111a+111b+111c=111(a+b+c)
111(a+b+c)divizibil cu :37
2 5 2
2014-11-10T19:54:49+02:00
Abc = 100a + 10b + c
bca = 100b + 10c + a
cab = 100c + 10a + b
100a + 10a + a + 100b  + 10b + b + 100c + 10c + c 
111a + 111b + 111c div cu 37
111(a + b + c ) ⇒ abc , bca , cab div cu 37 
111 : 37 = 3

3 4 3