Răspunsuri

2014-03-05T20:22:48+02:00
X , y , z- nr cautate 
x/3=y/7=z/11
x+2y+3z= 200
=> x/3 = y/7 = z/11=k => x=3k 
y=7k=> 2y = 14k
z=11k => 3z= 33k
=> 3k + 14k+ 33k = 200
50 k= 200|:50
k = 4 => x = 3x 4=12
y= 7x 4=28
z= 11x4=44
1 5 1