Răspunsuri

2014-11-09T20:04:33+02:00
7ab²+14a²b=7ab(b+2a)
-3,6x²y²+0,8x⁴y⁵=(-36/10)x²y²+(8/10)x⁴y⁵=4/10·x²y²(-9+2x²y³)=0,4x²y²(2x²y³-9)
2√17xy⁴-√17x²y=√17xy(2y³-x)
-15tz²-√(5t²z)=-15tz²-√5t√z=-t(15z²+√5√z)
x(3-y)+5(y-3)=3x-xy+5y-15
2,5a(a-1)-(1-a)=2,5a²-2,5a-1+a=2,5a²-1,5a-1