Răspunsuri

Cel mai inteligent răspuns!
2014-11-09T19:51:07+02:00
Ix+2I= x+2daca x+2≥0
          -x-2 daca x+2<0
deci avem 2 cazuri
a)1-(x+2)/6=(2x-1)/3-x aducem la acelasi numitor
(6-x-2)/6=(4x-2-6x)/6            :6
-x-8=-2x-2
-x+2x=8-2
x=6
b)
1-(-x-2)/6=(2x-1)/3-x
(6+x+2)/6=(4x-2-6x)/6
x+8=-2x-2
x+2x=-2-8
3x=-10
x=-10/3
x∈{-10/3,6}

2 5 2