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2014-11-08T19:57:26+02:00
Ab+cd=bc
10a+b+10c+d=10b+c
10a-9b+9c+d=0
10a-9(b-c)+d=0    dar b-c=d
10a-9d+d=0
10a=8d
5a=4d              a=4  d=5   
b= d+c = c+5 ≤9      rezulta c={1,2,3,4}
atunci b={6,7,8,9}
numerele sunt  4615, 4725,4835,4945  care verifica ambele conditii
46+15=61    6-1=5
47+25=72    7-2=5
48+35=83    8-3=5
49+45=94    9-4=5
  

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