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2014-11-08T20:59:30+02:00
Pentru pct 2 am gasit formula 

1²+2²+3²+......+n² =n(n+1)(2n+2)/6 
1²+2²+3²+......+100² =100(100+1)(2*100+2)/6  =100*101*201/6 = 50*101*67=
=338350