Răspunsuri

2014-11-08T16:59:30+02:00
A+b+c=250
a:b=2 ret 3⇒a=2·b+3
b:c=2 rest 3⇒b=2·c+3⇒c= \frac{b-3}{2}

trecem la inlocuiri
a+b+c=250
2·b+3+b+ \frac{b-3}{2} =250 aducem la acelasi numitor adica 2 ⇒
4·b+6+2·b+b-3=500
7·b+3=500
7·b=500-3
7·b=497
b=497:3
b=71

a=2·b+3=2·71+3=145⇒a=145

c=250-b-a=250-71-145=34⇒c=34