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  • Utilizator Brainly
2014-03-05T12:30:57+02:00
BD/DC=3/2 ⇒ (BD+DC)/DC=5/2 ⇒ DC=2BC/5=4√2 cm; BD=BC-DC=6√2 cm;
teorema inaltimii in ΔABC: AD²=BD·DC=48 cm ⇒ AD=√48=4√3 cm.
2 5 2
2014-03-05T12:32:23+02:00
BD/DC=3/2 deci BD/BC=3/5. BD/10radical2 =3/5 BD=6radical2 DC=4radical2 Din teorema inaltimii AD^2=6rad2*4rad2=48 Deci AD=4radical din 3