Răspunsuri

2014-11-06T20:16:49+02:00
2(3x-15+x)= 4(x-30-3x-3-1) --> 6x-30+2x=4x-120-12x-12-4 --> 8x-30=-8x-126 -->
16x=-126+30 --> x= 96/16 -->x=6
e 2[3(x-5)+x]=4(x-3)-3(x+1)-1
te rog fao asa
imi trb neaparat
2(3x-15+x) = 4x-12-3x-3 --> 6x-30+2x = x-15 --> 8x-30=x-15 --> 7x=15 --> x= 15/7 --> x=2, 1
nu da 2 fix , ci cu rest