Răspunsuri

2014-11-04T22:16:29+02:00
N : 2003=c rest 3*c cu 3*c< 2003 ⇒ c< 667,6 ⇒ c≤667
n=2003*0+0
n=2003*1+3
n=2003*2+6
...................
n=2003*667+2001
⇒ sunt 668 de nr care respecta cerinta
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