Răspunsuri

2014-11-04T21:02:47+02:00
/- supra ; *-inmultire; ^- putere
(3x+11/-1+x)*1/2=(5x-1/-1)*1/6
3x+11/-2+2x=5x-1/-6 ( de aici se inmultesc in cruce si =>
-6(3x+11)=(-2+2x)(5x-1)
-18x-66= -10x+2+10x^2-2x
10x^2 -2x-10x+18x+2+66=0
10x^2+6x+68=0
delta=b^2-4ac= 36-2720=-2684 => nu are radacini reale