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2014-11-04T11:42:05+02:00
5 \frac{1}{3} = \frac{3*5+1}{3} = \frac{16}{3}

\frac{16}{3} dublu; opusul sau este -2*\frac{16}{3} = -\frac{32}{3}

 \frac{16}{3} - \frac{32}{3} = \frac{16-32}{3} =- \frac{16}{3}

inversul numarului 2^{4} este \frac{1}{ 2^{4} } =2 ^{-4}

-\frac{16}{3} : \frac{1}{2 ^{4} } =-\frac{16}{3}*2 ^{4}=-\frac{16}{3}*16= -\frac{16*16}{3} =-\frac{256}{3}

(-\frac{256}{3}) ^{3} = -\frac{( 16^{2} ) ^{3} }{ 3^{3} } = -\frac{16 ^{2*3} }{3^{3} } =  -\frac{16^{6}}{3^{3}}  = -\frac{(2 ^{4}) ^{6}}{3^{3}} =- \frac{2 ^{4*6}}{3 ^{3} } =- \frac{2 ^{24}}{3 ^{3} }