Răspunsuri

2014-03-03T22:04:53+02:00
1 mol de atomi(1g) H contine 6,023ori10^{23} atomi de H 
                     10g H................ x atomi H
x=10 ori 6,023 ori  10^{23} = 60,23 ori 10^{23} atomi de hidrogen.

1 mol H_{2}  ⇒2 A_{H} = 2 ori 1 = 2g ⇒ n =  \frac{10g}{2g/mol} = 5 moli H_{2}

 \frac{ H_{2} }{5moli}+  \frac{ Cl_{2} }{xmoli} rezulta 2HCl

 \frac{1mol}{5moli} = \frac{1mol}{xmoli} rezulta x= \frac{1ori5}{1}= 5 moli  Cl_{2}

Asa cred ca vine :)
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