Răspunsuri

2014-11-03T21:42:01+02:00
3³+2x3∧5+3∧4=3³x(1+2x3²+3)=3³x(1+2x9+3)=3³x(1+18+3)=3³x22=27x22=594
5³x6+5∧4x7=5³x(6+5x7)=5³x(6+35)=5³x41=125x41=5125
7∧5xX+7∧4xY+49xZ=7∧5xX+7∧4xY+7²xZ=7²x(7³xX+7²xY+Z)=7²x(343X+49Y+Z)