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2014-11-04T19:37:14+02:00
FeCl₃ pur=25%
m NaOH=240
c NaOH=25%
m FeCl₃=?

Rezolvare.
 91.5     40
FeCl₃+NaOH=Fe(OH)₃+NaCl
  x          60
M FeCl=A Fe+A Cl=56+35.5=91.5
imol FeCl=91.5g
M NaOH=Na+A O+A H=23+16+1=40
1mol NaOH=40g

m NaOH pur=240·25=600=60g NaOH
                      100     10
x=91.5·60=549=137.25g
      40         4
R. m FeCl₃=137.25g