Răspunsuri

2014-11-03T09:36:48+02:00
Pai daca a(a+1)(a+2)=a(a+1)+48=>a(a+1)(a+2-1)=48=>a=3,b=4,c=5
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2014-11-03T09:40:08+02:00
Consideram numerele consecutive
a-1
a
a+1
(a-1) *a * (a+1) = (a-1) * a +48
(a-1) *a * (a+1) - (a-1) * a =48
a*(a-1) [(a+1) -1] =48
a*(a-1) *a = 48
a²(a-1) = 4² *3
a² =4²      ⇒a=4
a-1=4-1=3
a+1=4+1=5

verificare
3*4*5=60
3*4+48 = 12+48=60 

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