Răspunsuri

2014-11-02T18:48:42+02:00
(x²+y²)=305
(x-y)²=x²+y²-2xy
9²=305-2xy
2xy=305-81=
2xy=224
xy=112=2^4.7
acum exista mai multe posibilitati
xy=1.112=2.56=4.28=16.7=8.14
deci perechile de numere sunt
(1,112),(112,1),(2,56),(56,2),(4,28),(28,4),(16,7),(7,16),(8,14),(14,8)
unde perechile sunt de forma (x,y)