Răspunsuri

2014-11-02T09:45:37+02:00
Ab=bc=cd=da=24  
mo=dc/2    mo=24/2    mo=12
in triunghiul dom dreptunghic in o=90 grade avem;
do patrat=dm patrat-om patrat =>do=12
triunghiul dcb isoscel , co =inaltime => db=24
in triunghiul bdc isoscel    dm=inaltime  => mb=mc=bc/2=12
md=dcpatrat-mcpatrat    md=rd432   md=12rd3
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2014-11-02T09:51:15+02:00
Triunghiul MDC dreptunghic
MD=12  \sqrt{2}
DC=24
T Pitagora=>MC^2=MD^2+DC^2=288+576
=>MC=12 \sqrt{6}

Tringhiul MDB dreptunghic
DB=24 \sqrt{2}
MD=12 \sqrt{2}
T Pitagora=>MB^2=DB^2+MD^2=288+1152
MB=12 \sqrt{10}

Tringhiul MDO dreptunghic
MD=DO=12 \sqrt{2}
T Pitagora=>MO^2=MD^2+MO^2=288+288
=>MO=24
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