Răspunsuri

2014-03-03T14:38:51+02:00
A) 6a²·(2-a)+(3a-2)(a+1)-(3a+1)·(-a)²= =12a²-6a³+3a²+3a-2a-2•(-a)²= =-6a³+17a²+a b) (12a⁴+6a³-2a²)÷(-2a)+(36a⁴-24a⁵+18a⁶)÷(6a⁴)= =12a⁴+6a8+a+36a⁴-24a ⅝⅝
b) (12a⁴+6a³-2a²)÷(-2a)+(36a⁴-24a⁵+18a⁶)÷(6a⁴)= =12a⁴+6a8+a+36a⁴-24a⅝+3a²=
=6a8-24a⅝+48a⁴+3a²+a. Scz dar cand e ⅝ este fara 8.