Răspunsuri

2014-10-29T11:56:18+02:00
A) 3^2006 = 3² ·3^2004 = (1+4+4)·3^2004 =
= (3^1002)² +(2·3^1002)² +(2·3^1002)²
B) 3^2006 = 3^4 ·3^2002 = (1+16+64)·3^2002 =
= (3^1001)² + (4·3^1001)² + (8·3^1001)²