Răspunsuri

2014-10-28T21:59:59+02:00
A+2b+3c=2012
a+2a+2+3a+6=2012
6a+8=2012
6a=2008
a=334
b=a+1=335
c=a+2=336
2014-10-28T22:02:24+02:00
I nr:     I---------I
II nr     I---------I---------I+2
III nr:   I---------I---------I----------I+6
2012-6-2=2004
2004:6=334
deci primul nr.este 334
II:335 pt.ca sunt consecutive
III:336