Răspunsuri

2014-10-28T15:30:52+02:00
X^2+2x-3x-6=0

x^2-x-6=0

Δ=b^2-4ac=1-4*1*(-6)=1+24=25

x1=(-b+√Δ)/2a=(1+5)/2=6/2=3

x2=(-b-√Δ)/2a= (1-5)/2=-4/2=-2